3. T(t) = 38.6 + 3sin(öt/8)
a) 38.6 is the normal temperature
b) 38.6 + 3sin(öt/8) = 40
<=> 3sin(öt/8) = 1.4
<=> sin(öt/8) = 1.4/3 = 0.467
<=> öt/8 = sin-1(0.467) = 0.486
<=> t = 0.486*8/ö = 1.236
after about 1 and a quarter days.
4. Maximum is where sine is minimum
i.e. when D = 8 + 2 = 10metres
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